LSAT Analytical Reasoning questions require a critical approach to solve the riddle like questions. These questions test the analytical reasoning ability of the students to make logical conclusions. This portion is quite different from the other portions in the test. It requires a lot of practice and skill to solve the maze type questions.
Question No-8
LSAT Analytical Reasoning Question
Six cupboards, cupboard U, cupboard V, cupboard W, cupboard X, cupboard Y and cupboard Z are being placed in hotel rooms. Each of which can accommodated 2 cupboards and no more than two. Each cupboard must be placed in exactly one room and must be placed in that room either alone or else together with one other six cupboards. Enough rooms are available to permit any possible assignments of cupboards to rooms but the following restrictions must be observed.
- Cupboard V cannot be placed in a room with Cupboard W
- Cupboard W cannot be placed in a room with Cupboard X.
- Cupboard Y and Cupboard Z must be placed in a room together.
Q. No-1: Which of the following pairs of cupboards can be placed in one room together?
a. Cupboard U & Z
b. Cupboard W & X
c. Cupboard Y & V
d. Cupboard U & X
Q. No-2: If a cupboard is placed in a room alone, which of the following must be true?
a. Cupboard V is placed in room alone.
b. The cupboard occupies either 3 or 6 rooms.
c. None other than W is placed alone in a room.
d. The cupboard occupies either 4 or 5 rooms.
Q. No-3: If cupboards Y and Z are the only cupboards placed in a room, how many rooms are the minimum that can accommodate the cupboards?
a. 2
b. 3
c. 4
d. 5
Answer Key:
- D
- D
- B
Explanation of Each Question
Question 1: “Which of the following pairs of cupboards can be placed in one room together?”
Answer Key: D. Cupboard U and X
Explanation:
We need to check each pair against the restrictions:
a. Cupboard U and Z:
This option violates the rule that Y and Z must be placed together, so U and Z cannot be in the same room without Y.
b. Cupboard W and X:
This is not allowed because the rule specifically states W cannot be placed with X.
c. Cupboard Y and V:
This pairing is possible, but it doesn’t have to happen. More importantly, it’s not the only possible correct pair.
d. Cupboard U and X:
There is no rule preventing U and X from being placed together in a room. Therefore, this pair is allowed. D is correct because no rules are violated.
Thus, D is the correct answer.
Question 2: “If a cupboard is placed in a room alone, which of the following must be true?”
Answer Key: D. The cupboard occupies either 4 or 5 rooms.
Explanation:
Let’s consider how many rooms are required based on the rules:
Y and Z must be placed together, which takes one room.
The other cupboards (U, V, W, and X) either have to be placed alone or with another cupboard, following the restrictions.
Now, check each option:
a. Cupboard V is placed in a room alone:
This is not necessarily true. V can be paired with other cupboards, as long as it’s not paired with W.
b. The cupboard occupies either 3 or 6 rooms:
This is incorrect because at least 4 rooms will be needed. The minimum number of rooms is 4.
c. None other than W is placed alone in a room:
This is incorrect because it’s possible for other cupboards to be placed alone as well.
d. The cupboard occupies either 4 or 5 rooms:
This is correct. In the best case, you could use 4 rooms: Y and Z together in one room, and the remaining cupboards (U, V, W, X) in the other three rooms, either alone or in pairs. In the worst case, 5 rooms might be needed if some cupboards must be placed alone due to restrictions.
Answer Key: B. 3 rooms
Explanation:
- Since Y and Z must be placed together, that takes up one room. The remaining cupboards (U, V, W, X) need to be placed in the remaining rooms, and we need to minimize the number of rooms while still following the restrictions.
- V and W cannot be placed together, so they need separate rooms.
- W and X cannot be placed together, so they also need separate rooms.
Let’s count:
- Y and Z in one room (1 room).
- V cannot be with W, so V must be in a separate room (2 rooms).
- W cannot be with X, so W and X must go in different rooms (3 rooms total).
- Thus, the minimum number of rooms is 3, making B the correct answer.
